(q^2+3)/(2q-1)

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Solution for (q^2+3)/(2q-1) equation: 


D( q )

2*q-1 = 0

2*q-1 = 0

2*q-1 = 0

2*q-1 = 0 // + 1

2*q = 1 // : 2

q = 1/2

q in (-oo:1/2) U (1/2:+oo)

(q^2+3)/(2*q-1) = 0

1*q^2 = -3 // : 1

q^2 = -3

q belongs to the empty set

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